The Pridmore System for Card Memorization

My techniques aren't a secret, I'm quite happy to share them with
anyone who's interested. I normally point people towards the wwbc
posts last year where I explained it, but since we've got a brand
new group here, I've rewritten it and made it hopefully a bit easier
to understand. I don't actually call it the 'Ben system', but that's
what some people have been calling it, and I do quite like the name.
It's really just an extension of the basic Major system.
 
The basic principle is the same as everyone else uses, visualising
images at points along a mental route or journey. I don't use the
person-action-object ideas of some people, I just have
three `objects' at each point on my route. Some of these objects are
people, some are things. I `see' them arranged from left to right,
or top to bottom, and interacting in various ways according to rules
I made up as I went along, depending on which objects come together
in what order.
 
Each object is made from a combination of two playing cards, or
three decimal digits, or ten binary digits. The name of the object
starts with a one-syllable sound made up of a consonant, a vowel and
another consonant. For playing cards, these sounds are made as
follows.
 
The first consonant is given by the combination of suits, like this:
 
club/club - k
club/diamond - t
club/heart - n
club/spade - m
diamond/club - r
diamond/diamond - d
diamond/heart - l
diamond/spade - g/j
heart/club – f/th
heart/diamond - b
heart/heart - h
heart/spade - p
spade/club - sk/sn/sm
spade/diamond - st/sp
spade/heart - sh/sl/sw
spade/spade – s
 
The vowel comes from the number/rank of the first card, like this:
 
A = `a' as in `cat'
2 = 'e' as in 'pet'
3 = 'i' as in 'kitten'
4 = 'o' as in 'tom'
5 = 'u' as in 'puss'
6 = `A' as in `hay'
7 = `E' as in `bee'
8 = `I' as in `high'
9 = `O' as in `low'
10 = `oo' as in `you'
J = `ow' as in `cow'
Q = `or' as in `door'
K = `ar' as in `car'
 
And the final consonant comes from the number of the second card,
like this:
 
A = t
2 = n
3 = m
4 = r
5 = l
6 = g
7 = k
8 = f/th
9 = b
10 = s
J = j/sh/ch
Q = p
K = d
 
So, for example, Ace of hearts + 2 of clubs gives f (heart/club) + a
(Ace) + n (2) = `fan'. If the 2 of clubs came first it would be n
(club/heart) + e (2) + t (Ace) = `net'.
 
That gives me 2704 different images. For numbers, I use the same
list of images, but only use 1000 of them for decimal and 1024 for
binary. It works like this:
 
First consonant (first digit)
 
0 = s
1 = t
2 = n
3 = m
4 = r
5 = l
6 = gj
7 = k
8 = f/th
9 = b
 
Vowel (second digit)
 
0 = `oo'
1 = `a'
2 = 'e'
3 = 'i'
4 = 'o'
5 = 'u'
6 = `A'
7 = `E'
8 = `I'
9 = `O'
 
Second consonant (third digit)
 
0 = s
1 = t
2 = n
3 = m
4 = r
5 = l
6 = g
7 = k
8 = f/th
9 = b
 
And for binary, it's:
 
First consonant (first four digits)
 
0000 = s
0001 = t
0010 = n
0011 = m
0100 = r
0101 = l
0110 = g/j
0111 = k
1000 = f
1001 = b
1010 = p
1100 = h
1101 = sk/sn/sm
1110 = st/sp
1111 = sh/sl/sw
 
Vowel (next three digits)
 
000 = `oo'
001 = `a'
010 = 'e'
011 = 'i'
100 = 'o'
101 = 'u'
110 = `A'
111 = `E'
 
Second consonant (final three digits)
 
000 = s
001 = t
010 = n
011 = m
100 = r
101 = l
110 = g
111 = k
 
I hope that's clear. I'm always happy to answer questions!